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Brad Kallio
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Understanding wind energy.
WiND moving at 5 mph against 1 square foot surface will give you 2 lbs of force.
A kilowatt is equal to 750 lbs of force.
So to catch a kilowatt of wind energy in 5 mph wind you need 375 square feet of sale to catch a kilowatt in 5 mph wind.
This is why you done see airplane blades on sailboats!
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Peter VanDerWal
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Uhh, no.  Your math is incomplete.

A Kilowatt is a unit of "power", not "force".

Power = Force * Velocity

1 kilowatt = (approx) 737.46 foot pounds per second.  The "feet per second" part is pretty important.

The power in wind goes up at the cube of the wind speed.   There isn't much power in 5mph wind, assuming above average turbine efficiency, you'd need a turbine with approx 5,000 sqft of swept area to produce 1kw in a 5mph wind.
In a 15 mph wind, you'd only need 175 sqft, which is why most small turbines don't start producing power until the wind is at least 10-12 mph.

 
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