siphon experiment: moving water

Trying to figure out how to get water from my pond to the garden. The pond has a tall windmill beside it. I am considering running a hose up and over on of the cross members of the windmill support.

This will put the water elevation above the garden. I am thinking the length of the hose should overcome the problem of the water outlet being higher than the water inlet in the pond.

The length of hose from the pond to the windmill support will be app. 50'. The length of hose from the windmill support to my garden will be 300'. Will this amount of water on the downside of the siphon

overcome the fact that the "inlet" is lower than the "outlet"? Is there a formula for this type of siphon attempt?

This idea could easily cost a few hand pump sales I reckon. or am I a ding-a-ling for thinking this? :>)

Randy Gibson wrote:This idea could easily cost a few hand pump sales I reckon. or am I a ding-a-ling for thinking this? :>)

you're probably not a ding-a-ling, but this particular idea won't work. why not use the windmill to move the water?

the windmill aerates the pond. I will experiment with this theory and post results, eventually.

Falling liquid on the outlet side won't generate enough pressure to overcome atmospheric pressure on the inlet side unless the outlet is below the inlet. Outlet always has to be below inlet for a siphon to work.

I understand the theory of siphoning, I also think this can be overcome by adding height close to the water source and length to the downside. The ratio could be as high as 1000/1, but I believe it can be overcome.

Who knows, I may learn something new while wasting my time with this experiment. Thanks for the replies

water is always going to travel to the lowest point. in this case, that means it will drain back into your pond. it's likely that some of it will drain out the side you want as the pipe starts sucking air, but only until the pipe is drained.

however, if your windmill is aerating your pond, you could almost certainly use it to make an air lift pump. the idea is that air bubbling up through a tube will carry some water with it past the elevation of the water level. I think that's going to be your ticket. there's plenty of information concerning air lifts available.

A syphon will not work unless the outlet is lower than the inlet. Well, the surface of the water in the pond must be higher than the discharge end of the hose. What the hose does between the inlet and the outlet has nothing to do with if the syphon will go or not. It could do loop-de-loops and spell permiesdotcom, and it still won't work if the the outlet is higher than the inlet.

The air lift idea has merit.

How much water do you want to move per hour or day?

Finest regards,

troy

spiral pump ?

Though you CANNOT siphon to above the surface level of your water source. You may be able to set up an air lift pump using the windmills output.

I am going to experiment with this idea. I am convinced the weight of the water at each end of the siphon will make a difference. There is much left to be learned on this earth.

you can use the weight of it to lift, but it will take a ram pump.
very expensive option with the airlift, or windwill pump availible