So I have looked at the batch box style and think that is the way for me to go.
I have seen all the ways to figure up the size of the stove, with the exception of how to size it to the house.
I have seen one formula: Q=G*V*DT
Where Q is the amount of Kw required
G is an insulation factor.
V is the volume of the house (m3)
And DT is the difference in temperature from outside to inside.
I have a dome home that is 36' in diameter.
That gives me a Volume of 346 m3.
For my house I chose to use the insulating factor 1.6
and my DT is 25 degrees celsius.
According to that formula my Kw requirement would be 13840 or 13.8 Kw
According to the chart, there is no way for a batch box to heat my house.
The bigger the internal diameter, the heavier the load of
wood for each fire:
Internal diameter (mm) -- Wood load (kg) -- Mean power considering two fires a day (kW)
125 mm — 3.5 kg — 1.1 kW
140 mm — 4.9 kg — 1.5 kW
150 mm — 6.0 kg — 1.9 kW
175 mm — 9.5 kg — 2.9 kW
200 mm — 14.2 kg — 4.4 kW
230 mm — 21.6 kg — 6.7 kW
250 mm — 27.8 kg — 8.6 kW
Considering that a 250 mm stove is a 10 inch stove.
There must be a problem with either the formula or my math skills.
My numbers are: Q= 1.6 * 346 * 25 so Q= 13840
Can anyone advise me on this? What have I missed?
Thanks in advance.
I really want to use one of these.